Answer
$\frac{25}{7776}$
Work Step by Step
$P(E)=1-P(\text{not E})$. Since the events are independent, $P(\text{A and B})=P(A)P(B)$.
Hence here the probability: $\frac{1}{6}\frac{5}{6}\frac{1}{6}\frac{1}{6}\frac{5}{6}=\frac{25}{7776}$
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 748: 87
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
