Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 748: 61

Answer

$\frac{109}{121}\approx0.90$

Work Step by Step

The total number of outcomes in this sample: $242$ (million), the number of outcomes satisfying the requirements in this sample: $242-24=218$ (million), thus the probability: $\frac{218}{242}=\frac{109}{121}\approx0.90$
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