Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 748: 81

See below.

We know that $P(\text{A and B})=P(A)P(B)$ when the events are independent. Hence here the exercise can be to find the probability of drawing a $4$ from a hat containing a paper with the integers $1$ to $4$ and then drawing an odd number from a different hat containing a paper with the integers $1$ to $5$.