Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 748: 84

Answer

Makes sense.

Work Step by Step

Makes sense, because $P(E)=1-P(\text{not E})$.
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