Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.5 Volume and Surface Area - Exercise Set 10.5 - Page 657: 36

Answer

\[\frac{1}{27}\]

Work Step by Step

Compute the volume of the sphere having radius 3 inches using the equation as shown below: \[\begin{align} & \text{Volume of the Sphere (}{{V}_{1}}\text{)}=\frac{4}{3}\pi {{r}^{3}} \\ & =\frac{4}{3}\left( \pi {{\left( 3 \right)}^{3}} \right)\text{i}{{\text{n}}^{3}} \\ & =36\pi \text{ i}{{\text{n}}^{3}} \end{align}\] Again, compute the volume of the sphere having radius 9 inches using the equation as shown below: \[\begin{align} & \text{Volume of the Sphere (}{{V}_{2}}\text{)}=\frac{4}{3}\pi {{r}^{3}} \\ & =\frac{4}{3}\left( \pi {{\left( 9 \right)}^{3}} \right)\text{i}{{\text{n}}^{3}} \\ & =972\pi \text{ i}{{\text{n}}^{3}} \end{align}\] Now, compute the required ratio using the equation as shown below: \[\begin{align} & \text{Ratio}=\frac{{{V}_{1}}}{{{V}_{2}}} \\ & =\frac{36\pi \text{ i}{{\text{n}}^{3}}}{972\pi \text{ i}{{\text{n}}^{3}}} \\ & =\frac{36}{972} \\ & =\frac{1}{27} \end{align}\]
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