Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.5 Volume and Surface Area - Exercise Set 10.5 - Page 657: 26

Answer

The volume of the given figure is\[150\pi \text{ c}{{\text{m}}^{3}}\]or\[471\text{ c}{{\text{m}}^{3}}\].

Work Step by Step

The diameter and height of the given figure is 10 cm and 8 cm, respectively. To compute the volume of the figure, firstly compute the volume of the upper part, which is a hemisphere. Secondly, compute the volume of the lower part, which is a cone. Finally, add the volume of both the upper and lower parts to ascertain the volume of the given figure. Firstly, compute the radius of the given figure using the equation: \[\begin{align} & \text{Radius}=\left( \frac{1}{2}\times 10 \right)\text{cm} \\ & =5\text{ cm} \end{align}\] Compute the volume of the upper part that is hemisphere using the equation as shown below: \[\begin{align} & \text{Volume of the Hemisphere }\left( V \right)=\frac{2}{3}\left( \pi {{\left( 5\text{ cm} \right)}^{3}} \right) \\ & =83\pi \text{ c}{{\text{m}}^{3}} \end{align}\] Compute the volume of the lower part that is cone using the equation as shown below: \[\begin{align} & \text{Volume of the Cone (}V\text{)}=\frac{1}{3}\left( \pi {{\left( 5\text{ cm} \right)}^{2}}8\text{ cm} \right) \\ & =67\pi \text{ c}{{\text{m}}^{3}} \end{align}\] Now, compute the volume of the given figure using the equation as shown below: \[\begin{align} & \text{Volume of the figure}=\text{Volume of upper part}+\text{Volume of lower part} \\ & \text{=}\left( 83\pi +67\pi \right)\text{c}{{\text{m}}^{3}} \\ & =150\pi \text{ c}{{\text{m}}^{3}} \\ & =471\text{ c}{{\text{m}}^{3}} \end{align}\]
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