Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.5 Volume and Surface Area - Exercise Set 10.5 - Page 657: 29

Answer

The volume of the given figure is\[\frac{3,332}{3}\pi \text{ }{{\text{m}}^{3}}\]or\[3,489\text{ }{{\text{m}}^{3}}\].

Work Step by Step

The diameter and height of the lower part, which is a cylinder are 14m and 18m respectively. The diameter of the upper part, which is a sphere is 14m. In order to compute the volume of the figure, firstly compute the volume of the upper part, which is a sphere. Secondly, compute the volume of the lower part which is a cylinder. Finally, add the volume of both the upper and lower parts to ascertain the volume of the given figure. Compute the radius of the given figure using the equation: \[\begin{align} & \text{Radius}=\left( \frac{1}{2}\times 14\text{ m} \right) \\ & =7\text{ m} \end{align}\] Compute the volume of the upper part that is hemisphere using the equation as shown below: \[\begin{align} & \text{Volume of the Hemispherical part }\left( V \right)=\frac{2}{3}\pi {{r}^{3}} \\ & =\frac{2}{3}\left( \pi {{\left( 7\text{ m} \right)}^{3}} \right) \\ & =\frac{686}{3}\pi \text{ }{{\text{m}}^{3}} \end{align}\] Compute the volume of the lower part that is cylinder using the equation as shown below: \[\begin{align} & \text{Volume of the cylindrical part (}V\text{)}=\pi {{r}^{2}}h \\ & =\left( \pi {{\left( 7\text{ m} \right)}^{2}}18\text{ m} \right) \\ & =882\pi \text{ }{{\text{m}}^{3}} \end{align}\] Now, compute the volume of the given figure using the equation as shown below: \[\begin{align} & \text{Volume of the figure}=\text{Volume of upper part}+\text{Volume of lower part} \\ & \text{=}\left( \frac{686}{3}\pi +882\pi \right){{\text{m}}^{3}} \\ & =\frac{3,332\pi }{3}{{\text{m}}^{3}} \\ & =3849\text{ }{{\text{m}}^{3}} \end{align}\]s
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