Answer
$z=\frac{53}{9}$
Work Step by Step
We are given the equation $z-\frac{7}{3}=\frac{32}{9}$.
Add $\frac{7}{3}$ to both sides.
$z-\frac{7}{3}+\frac{7}{3}=\frac{32}{9}+\frac{7}{3}$
$z+0=\frac{32}{9}+\frac{7}{3}=\frac{32}{9}+\frac{7\times3}{3\times3}=\frac{32}{9}+\frac{21}{9}=\frac{32+21}{9}=\frac{53}{9}$
$z+0=\frac{53}{9}$
Therefore, $z=\frac{53}{9}$.
