Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 669: 27



Work Step by Step

We are given the equation $d+\frac{2}{3}=3$. Subtract $\frac{2}{3}$ from both sides. $d+\frac{2}{3}-\frac{2}{3}=3-\frac{2}{3}$ $d+0=3-\frac{2}{3}=\frac{9}{3}-\frac{2}{3}=\frac{9-2}{3}=\frac{7}{3}$ $d+0=\frac{7}{3}$ Therefore, $d=\frac{7}{3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.