Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 669: 32



Work Step by Step

We are given the equation $\frac{3}{5}=t-1$. Add 1 to both sides. $\frac{3}{5}+1=t-1+1$ $\frac{3}{5}+1=\frac{3}{5}+\frac{5}{5}=\frac{3+5}{5}=\frac{8}{5}=t+0$ $\frac{8}{5}=t+0$ Therefore, $t=\frac{8}{5}$.
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