Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 669: 33

Answer

$m=\frac{83}{20}$

Work Step by Step

We are given the equation $m-\frac{7}{5}=\frac{11}{4}$. Add $\frac{7}{5}$ to both sides. $m-\frac{7}{5}+\frac{7}{5}=\frac{11}{4}+\frac{7}{5}$ $m+0=\frac{11}{4}+\frac{7}{5}=\frac{11\times5}{4\times5}+\frac{7\times4}{5\times4}=\frac{55}{20}+\frac{28}{20}=\frac{55+28}{20}=\frac{83}{20}$ $m+0=\frac{83}{20}$ Therefore, $m=\frac{83}{20}$.
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