Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 564: 9

Answer

Area of the Triangle = $A$ = 302.46 cm$^{2}$ Perimeter of the Triangle = $P$ = 85.2 cm

Work Step by Step

Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(21.3 cm)(28.4 cm) $A$ = 302.46 cm$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 35.5 cm + 21.3 cm + 28.4 cm $P$ = 85.2 cm
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.