Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 564: 11


Total Area of the Shape: 198 m$^{2}$

Work Step by Step

To find the area of the shape we simply find the area of the triangle and sum it with the area of the square. Area of a Square: $A$$_{square}$ = $s$$^{2}$ Therefore: $A$$_{square}$ = (12 m)$^{2}$ $A$$_{square}$ = 144 m$^{2}$ Area of a Triangle: $A$$_{tri}$ = $\frac{1}{2}$$b$$h$ Therefore: $A$$_{tri}$ =$\frac{1}{2}$(12 m)(9 m) $A$$_{tri}$ = 54 m$^{2}$ $A$$_{total}$ = $A$$_{square}$ + $A$$_{tri}$ Therefore: $A$$_{total}$ = 144 m$^{2}$ + 54 m$^{2}$ $A$$_{total}$ = 198 m$^{2}$
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