## Basic College Mathematics (10th Edition)

The area of the triangle is $30.75$ yd$^{2}$ and the perimeter is $26.25$ yd.
1. Find the area of the triangle Let $A =$ area of the triangle $A = base \times height \div 2$ $A = (10.25 \times 6) \div 2$ $A = 30.75$ yd$^{2}$ 2. Find the perimeter of the triangle Let $P =$ perimeter of the triangle $P = a + b + c$ $P = 9 + 7 + 10.25$ $P = 26.25$ yd