## Basic College Mathematics (10th Edition)

Area of the Triangle = $A$ = 52 yd$^{2}$ Perimeter of the Triangle = $P$ = 34 yd
Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(13 yd)(8 yd) $A$ = 52 yd$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 9 yd + 12 yd + 13 yd $P$ = 34 yd