Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Mixed Review Exercises - Page 257: 9

Answer

$15\frac{5}{12}$

Work Step by Step

$32\frac{5}{12}-17$ Now. convert mixed fractions into improper fractions, = $\frac{32\times12+5}{12}-\frac{17}{1}$ = $\frac{389}{12}-\frac{17}{1}$ now the least common multiple of 12 & 1 is 12. so multiply the nominator and denominator of second fraction with 12 . = $\frac{389}{12}-\frac{17\times12}{1\times12}$ = $\frac{389}{12}-\frac{204}{12}$ Subtract numerators, as all fractions have same denominator = $\frac{389-204}{12}$ = $\frac{185}{12}$ = $15\frac{5}{12}$
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