## Basic College Mathematics (10th Edition)

$11\frac{43}{80}$
$2\frac{3}{5}+8\frac{5}{8}+\frac{5}{16}$ Now. convert mixed fractions into improper fractions, = $\frac{2\times5+3}{5}+\frac{8\times8+5}{8}+\frac{5}{16}$ = $\frac{13}{5}+\frac{69}{8}+\frac{5}{16}$ now the least common multiple of 5, 8 & 16 is 80. so multiply the nominator and denominator of first fraction with 16, second fraction by 10 and third fraction by 5. = $\frac{13\times16}{5\times16}+\frac{69\times10}{8\times10}+\frac{5\times5}{16\times5}$ = $\frac{208}{80}+\frac{690}{80}+\frac{25}{80}$ Add numerators, as all fractions have same denominator = $\frac{208+690+25}{80}$ = $\frac{923}{80}$ = $11\frac{43}{80}$