Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Mixed Review Exercises - Page 257: 7

Answer

$5\frac{3}{8}$

Work Step by Step

$7-1\frac{5}{8}$ Now. convert mixed fractions into improper fractions, = $7-\frac{8\times1+5}{8}$ = $7-\frac{13}{8}$ now the least common multiple of 1 & 8 is 8. so multiply the nominator and denominator of first fraction with 8. $\frac{7\times8}{1\times8}-\frac{13}{8}$ = $\frac{56}{8}-\frac{13}{8}$ Subtract numerators, as all fractions have same denominator = $\frac{56-13}{8}$ = $\frac{43}{8}$ = $5\frac{3}{8}$
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