Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Mixed Review Exercises - Page 257: 5

Answer

$2\frac{1}{6}$

Work Step by Step

$6\frac{2}{3}-4\frac{1}{2}$ Now. convert mixed fractions into improper fractions, = $\frac{6\times3+2}{3}-\frac{4\times2+1}{2}$ = $\frac{20}{3}-\frac{9}{2}$ now the least common multiple of 3 & 2 is 6. so multiply the nominator and denominator of first fraction with 2 and second fraction by 3. $\frac{20\times2}{3\times2}-\frac{9\times3}{2\times3}$ = $\frac{40}{6}-\frac{27}{6}$ Subtract numerators, as all fractions have same denominator = $\frac{40-27}{6}$ = $\frac{13}{6}$ = $2\frac{1}{6}$
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