Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises: 34

Answer

r = 4 in. slant height = 8 in. h $\approx$ 6,9 ft

Work Step by Step

Slant height = 2 r Total area = $\pi$ $r^{2}$ + $\pi$ r (slant height) Total area = $\pi$ $r^{2}$ + $\pi$ r (2 r) Total area = $\pi$ $r^{2} + 2 \pi$ $r^{2}$ Total area = 3 $\pi$ $r^{2}$ 48 $\pi$ $in.^{2}$ = 3 $\pi$ $r^{2}$ $r^{2}$ = 16 $in.^{2}$ r = 4 in. slant height = 8 in. h = $\sqrt (slant height)^{2} - r^{2}$ h = $\sqrt 64 ft^{2} - 16 ft^{2}$ h $\approx$ 6,9 ft
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