Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises: 29

Answer

65 $\pi$ $cm^{2}$

Work Step by Step

V = $\frac{\pi r^{2} h}{3}$ h = $\frac{3 V}{ \pi r^{2}}$ h = $\frac{3 \times 100\pi cm^{3}}{ \pi 25 cm^{2}}$ h = 12 cm a = $\sqrt (h^{2} + r^{2} )$ a = $\sqrt (144 cm^{2} + 25 cm^{2}) $ a = 13 cm Lateral area = $\pi$ r a Lateral area = $\pi$ $\times$ 5 cm $\times$ 13 cm Lateral area = 65 $\pi$ $cm^{2}$
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