Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises - Page 432: 30

Answer

$\approx$ 599.5 $ft^{3}$

Work Step by Step

lateral area = $\pi$ $\times$ r $\times$ slant height r = $\frac{96 \pi ft^{2}}{\pi 12 ft }$ r = 8 ft h = $\sqrt (slant height)^{2} - r^{2}$ h = $\sqrt 144 ft^{2} - 64 ft^{2}$ h = 4 $\sqrt 5 $ ft Volume = $\frac{\pi r^{2} h}{3}$ Volume = $\frac{\pi \times (8 ft)^{2} \times 4 \sqrt 5 ft }{3}$ Volume $\approx$ 599.5 $ft^{3}$
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