Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises - Page 432: 28

Answer

$36\pi$

Work Step by Step

The radius of this sphere was 3. Thus: $V = \frac{4}{3}\pi r^3 \\ V = \frac{4}{3}\pi 3^3 = 36 \pi$
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