Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 378: 8

Answer

24 $cm^{2}$

Work Step by Step

Given the area of the sector = 40 $cm^{2}$ Area of the $\triangle$ MON = 16 $cm^{2}$ So the area of the segment = area of the sector - area of the triangle = 40 - 16 = 24 $cm^{2}$
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