#### Answer

24 $cm^{2}$

#### Work Step by Step

Given the area of the sector = 40 $cm^{2}$
Area of the $\triangle$ MON = 16 $cm^{2}$
So the area of the segment = area of the sector - area of the triangle
= 40 - 16
= 24 $cm^{2}$

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Published by
Cengage

ISBN 10:
978-1-337-61408-5

ISBN 13:
978-1-33761-408-5

24 $cm^{2}$

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