## Elementary Geometry for College Students (7th Edition) Clone

Perimeter = 24 + 9$\pi$ in Area = $24 \pi in^{2}$
Perimeter of sector = 2*radius + l(CD) In a circle whose circumference is c, the length l of an arc whose degree measure is m is given by l =$\frac{m}{360}$ * c Therefore for given circle c = 2$\pi$ r = 2$\pi$ * 12 = 24$\pi$ in l =$\frac{135}{360}$ * 24$\pi$ in = $\frac{3}{8}$ * 24$\pi$ in = 9$\pi$ in Perimeter of sector = 2* radius + l = 2* 12 +9$\pi$ in = 24 + 9$\pi$ in In a circle of radius length r , the Area A of the sector whose arc has degree measure m is A = $\frac{m}{360}$ * $\pi r^{2}$ = $\frac{60}{360}$ * $\pi 12^{2}$ = $\frac{1}{6}$ * 144$\pi$ = $24 \pi in^{2}$ Therefore the area of the sector = $24 \pi in^{2}$