## Elementary Geometry for College Students (7th Edition)

30$in^{2}$
A circle is inscribed in a triangle having sides of length 5in, 12in 13 in the length of the radius of the inscribed circle is 2 in. We need to find the area of the triangle Where P represents the perimeter of a triangle and r represents the length of the radius of its inscribed circle, the area of the triangle is given by A = $\frac{1}{2}$rP Perimeter of triangle = 5+ 12+ 13= 30 in A = $\frac{1}{2}$rP A = $\frac{1}{2}$*2* 30= 30$in^{2}$