Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 378: 13

Answer

24 $in^{2}$

Work Step by Step

A circle is inscribed in a triangle having sides of length 6in, 8in, and 10in the length of the radius of the inscribed circle is 2 in. We need to find the area of the triangle Where P represents the perimeter of a triangle and r represents the length of the radius of its inscribed circle, the area of the triangle is given by A = $\frac{1}{2}$rP Perimeter of triangle = 6+8+10 = 24 in A = $\frac{1}{2}$rP A = $\frac{1}{2}$*2*24 = 24 $in^{2}$
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