Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Review Exercises - Page 315: 9


arc AD=173.33$^{\circ}$ arc AC=93.33$^{\circ}$ arc DC=93.33$^{\circ}$

Work Step by Step

2m$\angle$B=AD-($\frac{360-AD}{2}$) 80-AD=-$\frac{360-AD}{2}$ 160-2AD=-360+AD 3AD=520 AD=173.33 AC=DC=$\frac{360-AD}{2}$ AC=DC=93.33
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