Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Review Exercises - Page 315: 23e

Answer

arc AB=90$^{\circ}$ arc CD=40$^{\circ}$

Work Step by Step

AB-CD=2m$\angle$P AB=50+CD AB+CD=130 CD=130-AB CD=130-(50+CD) CD=80-CD 2CD=80 CD=40$^{\circ}$ AB=50+CD AB=90$^{\circ}$
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