Answer
arc AB=90$^{\circ}$
arc CD=40$^{\circ}$
Work Step by Step
AB-CD=2m$\angle$P
AB=50+CD
AB+CD=130
CD=130-AB
CD=130-(50+CD)
CD=80-CD
2CD=80
CD=40$^{\circ}$
AB=50+CD
AB=90$^{\circ}$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 6 - Review Exercises - Page 315: 23e
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