Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Review Exercises - Page 315: 23f

Answer

260$^{\circ}$

Work Step by Step

.5(AB+CD)=m$\angle$CED AB+CD=100 AC+BD=360-AB+CD AC+BD=360-100 AC+BD=260$^{\circ}$
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