Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Review Exercises - Page 315: 24g



Work Step by Step

We use the theorems in the chapter to obtain: $EC CD = AC BC \\ 2ED(CD) = 3(30)$ We know CD and ED are equal, so we find: $2ED^2 = 90 \\ ED = \sqrt{45}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.