## Elementary Geometry for College Students (7th Edition)

Published by Cengage

# Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 6b

#### Answer

$8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β

#### Work Step by Step

Given data a=6,b =8, c=9 Using theorem 11.4.3 In triangle ABC $b^{2}$ = $a^{2}$ + $c^{2}$ - 2ac cos β $8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β

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