## Elementary Geometry for College Students (7th Edition)

Published by Cengage

# Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 5a

#### Answer

$c^{2}$ = $(7.9)^{2}$ + $(5.2)^{2}$ + 2*5.2*7.9 cos 83°

#### Work Step by Step

Given data a=5.2,b=7.9, γ=83° Using theorem 11.4.3 $c^{2}$ = $b^{2}$ + $a^{2}$ + 2ab cos γ $c^{2}$ = $(7.9)^{2}$ + $(5.2)^{2}$ + 2*5.2*7.9 cos 83° $c^{2}$ = $(7.9)^{2}$ + $(5.2)^{2}$ + 2*5.2*7.9 cos 83°

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