Answer
$\frac{sine 41°}{5.3}$ = $\frac{sine 87°}{c}$
Work Step by Step
Given a=5.3, α =41° and γ=87°
By law of sines
$\frac{sine α}{a}$ = $\frac{sine γ}{c}$
$\frac{sine 41°}{5.3}$ = $\frac{sine 87°}{c}$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 3b
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