## Elementary Geometry for College Students (7th Edition)

$\frac{sine 41°}{5.3}$ = $\frac{sine 87°}{c}$
Given a=5.3, α =41° and γ=87° By law of sines $\frac{sine α}{a}$ = $\frac{sine γ}{c}$ $\frac{sine 41°}{5.3}$ = $\frac{sine 87°}{c}$