# Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 1a

Area = $\frac{1}{2}$* 5*6* sin78°

#### Work Step by Step

Using theorem 11.4.1 The area of the given triangle is = $\frac{1}{2}$ab sinγ Given a =5 b=6 and γ = 78° therefore Area = $\frac{1}{2}$* 5*6* sin78°

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