Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 504: 4

Answer

sin(a) = $\frac{\sqrt 5}{3}$ sin(b) = $\frac{2}{3}$

Work Step by Step

The opposite side of angle a is $\sqrt 5$ and hypotenuse is 3. Therefore sin(a) = $\frac{\sqrt 5}{3}$ The opposite side of angle b is unknown and hypotenuse is 3. To find the unknown opposite side, use Pythagorus theorem. $3^{2}$ - $\sqrt 5^{2}$ = $x^{2}$ 9 - 5 = $x^{2}$ $x^{2}$ = 4 x = 2 So sin(b) = $\frac{2}{3}$
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