Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 504: 15

Answer

$a\approx6.9$ in. $b\approx9.8$ in.

Work Step by Step

$\sin35^{\circ}=\frac{a}{12}$ $a=12\times\sin35^{\circ}$ $a\approx6.9$ Using Pythagorean Theorem to find $b$. $b=\sqrt {12^{2}-a^{2}}$ $b\approx\sqrt{12^{2}-6.9^{2}}$ $b\approx9.8$
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