Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 504: 16

Answer

$a\approx13.6$ m $b\approx14.7$ m

Work Step by Step

$\sin43^{\circ}=\frac{a}{20}$ $a=20\times\sin43^{\circ}$ $a\approx13.6$ Using Pythagorean Theorem to find $b$. $b=\sqrt {20^{2}-a^{2}}$ $b\approx\sqrt{20^{2}-13.6^{2}}$ $b\approx14.7$
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