Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 504: 3

Answer

sin α = $\frac{8}{17}$ sin β = $\frac{15}{17}$

Work Step by Step

In given right triangle, applying Pythagorean theorem- $17^{2} = a^{2} + 15^{2}$ Therefore- $a^{2} = 17^{2} - 15^{2}$ = 289 - 225 = 64 a = $\sqrt {64}$ = 8 sin α=$\frac{opposite}{hypotenuse}=\frac{a}{17}=\frac{8}{17}$ sin β=$\frac{opposite}{hypotenuse}=\frac{15}{17}$
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