#### Answer

$12\pi$

#### Work Step by Step

We first find the height of the circle:
$h = \sqrt{8^2 - 4^2} = \sqrt{48} = 4\sqrt{3}$
Since this height is double the radius, we find: $r = 2 \sqrt{3}$
Thus, we find area:
$ A = \pi(2\sqrt{3})^2 = 12\pi$

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Published by
Brooks Cole

ISBN 10:
9781285195698

ISBN 13:
978-1-28519-569-8

$12\pi$

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