# Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 374: 45

15.7 ft/sec

#### Work Step by Step

Given The diameter of a carousel (merry-go-round) is 30 ft. At full speed, it makes a complete revolution in 6 s. We need to find out At what rate, in feet per second, is a horse on the outer edge moving Rate = $\frac{total distance traveled in one revolution}{time taken for one revolution}$ = $\frac{Perimeter o the circular path}{time taken to cover one revolution}$ = $\frac{2\pi r}{6}$ = $\frac{\pi d}{6}$ = $\frac{\pi * 30}{6}$ = 5$\pi$ = 15.7 ft/sec

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