Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 374: 44


$\approx$16.76 feet per second

Work Step by Step

Given The radius of the Ferris wheel’s circular path is 40 ft. If a “ride” of 12 revolutions is made in 3 minutes, at what rate in feet per second is the passenger in a cart moving during the ride Given radius of the wheel = 40 ft So one revolution = circumference of the wheel = 2 * $\pi$ * 40 = 80$\pi$ The wheel rotate 12 times for a ride, So total circumference = 12 * 80$\pi$ = 960 $\pi$ As we know speed = $\frac{distance}{time}$ = $\frac{ 960 \pi}{ 3 min}$ = $\frac{960 \pi}{180 sec}$ ( as we know 1 min = 60 sec) = 16.76 feet per sec So the passenger in a cart moving during the ride at a rate of 16.76 feet per second.
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