## Elementary Geometry for College Students (6th Edition)

Given A track is to be constructed around the football field at a junior high school. If the straightaways are 100 yd in length, The total length around the track is 440yd The total length of the track = 100 +100 + 2*Circumference of the two semi circles = 100 + 100 + 2$\frac{2\pi r}{2}$ 440 yd = 200 + 2($\pi$ r) 2($\pi$ r) = 440 -200 2($\pi$ r) = 240 $\pi$ r = $\frac{240}{2}$ r = $\frac{120}{\pi}$ = 38.19 yd