Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 496: 22

Answer

$\alpha\approx44^{\circ}$ $\beta\approx46^{\circ}$

Work Step by Step

$\sin\alpha=\frac{14}{20}$ $\alpha=\sin^{-1}\frac{14}{20}$ $\alpha\approx44^{\circ}$ Sum of interior angles of a triangle $= 180^{\circ}$ $90^{\circ} + \alpha + \beta = 180^{\circ}$ $90^{\circ} + 44^{\circ} + \beta \approx 180^{\circ}$ $\beta\approx46^{\circ}$
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