Answer
$a\approx13.6$ m
$b\approx14.7$ m
Work Step by Step
$\sin43^{\circ}=\frac{a}{20}$
$a=20\times\sin43^{\circ}$
$a\approx13.6$
Using Pythagorean Theorem to find $b$.
$b=\sqrt {20^{2}-a^{2}}$
$b\approx\sqrt{20^{2}-13.6^{2}}$
$b\approx14.7$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 496: 16
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