## Elementary Geometry for College Students (6th Edition)

$a\approx13.6$ m $b\approx14.7$ m
$\sin43^{\circ}=\frac{a}{20}$ $a=20\times\sin43^{\circ}$ $a\approx13.6$ Using Pythagorean Theorem to find $b$. $b=\sqrt {20^{2}-a^{2}}$ $b\approx\sqrt{20^{2}-13.6^{2}}$ $b\approx14.7$