Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 496: 2

Answer

$\sin\alpha=\frac{3}{5}$ $\sin\beta=\frac{4}{5}$

Work Step by Step

$\sin\alpha=\frac{opposite}{hypotenuse}=\frac{6}{10}=\frac{3}{5}$ $\sin\beta=\frac{opposite}{hypotenuse}=\frac{8}{10}=\frac{4}{5}$
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