Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 496: 1

Answer

$\sin\alpha = \frac{5}{13}$ $\sin\beta = \frac{12}{13}$

Work Step by Step

$\sin\alpha=\frac{opposite}{hypotenuse}=\frac{5}{13}$ $\sin\beta=\frac{opposite}{hypotenuse}=\frac{12}{13}$
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