# Chapter 10 - Section 10.6 - The Three-Dimensional Coordinate System - Exercises - Page 482: 4

A direction vector for the line is: $\langle 3, -2, -3 \rangle$

#### Work Step by Step

$P_1 = (-1,5,2)$ $P_2 = (2,3,-1)$ We can find a direction vector through the two points: $\langle x_2-x_1, y_2-y_1, z_2-z_1\rangle$ $= \langle 2-(-1), 3-5, -1-2 \rangle$ $= \langle 3, -2, -3 \rangle$ A direction vector for the line is: $\langle 3, -2, -3 \rangle$

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