Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 10 - Section 10.6 - The Three-Dimensional Coordinate System - Exercises - Page 481: 3

Answer

A direction vector for the line is: $\langle 2, 3, -1 \rangle$

Work Step by Step

$P_1 = (0,0,0)$ $P_2 = (2,3,-1)$ We can find a direction vector through the two points: $\langle x_2-x_1, y_2-y_1, z_2-z_1\rangle$ $= \langle 2-0, 3-0, -1-0 \rangle$ $= \langle 2, 3, -1 \rangle$ A direction vector for the line is: $\langle 2, 3, -1 \rangle$
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