Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 10 - Section 10.6 - The Three-Dimensional Coordinate System - Exercises - Page 482: 12

Answer

$d = 7.81$

Work Step by Step

$P_1 = (-1,2,3)$ $P_2 = (2,-2,9)$ We can find the distance between these two points: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$ $d = \sqrt{(2-(-1))^2+((-2)-2)^2+(9-3)^2}$ $d = \sqrt{(3)^2+(-4)^2+(6)^2}$ $d = \sqrt{9+16+36}$ $d = \sqrt{61}$ $d = 7.81$
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